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Câu hỏi: Chọn kết quả sai trong các kết quả dưới đây:
A. $\underset{x\to {{x}_{0}}}{\mathop{\lim }} x={{x}_{0}}$
B. $\underset{x\to -\infty }{\mathop{\lim }} {{x}^{5}}=-\infty $
C. $\underset{x\to +\infty }{\mathop{\lim }} \dfrac{2}{{{x}^{2}}}=+\infty $
D. $\underset{x\to {{1}^{+}}}{\mathop{\lim }} c=c$
A. $\underset{x\to {{x}_{0}}}{\mathop{\lim }} x={{x}_{0}}$
B. $\underset{x\to -\infty }{\mathop{\lim }} {{x}^{5}}=-\infty $
C. $\underset{x\to +\infty }{\mathop{\lim }} \dfrac{2}{{{x}^{2}}}=+\infty $
D. $\underset{x\to {{1}^{+}}}{\mathop{\lim }} c=c$
Ta có:
$\underset{x\to {{x}_{0}}}{\mathop{\lim }} x={{x}_{0}}$
$\underset{x\to -\infty }{\mathop{\lim }} {{x}^{5}}=-\infty $
$\underset{x\to +\infty }{\mathop{\lim }} \dfrac{2}{{{x}^{2}}}=0$
$\underset{x\to {{1}^{+}}}{\mathop{\lim }} c=c.$
$\underset{x\to {{x}_{0}}}{\mathop{\lim }} x={{x}_{0}}$
$\underset{x\to -\infty }{\mathop{\lim }} {{x}^{5}}=-\infty $
$\underset{x\to +\infty }{\mathop{\lim }} \dfrac{2}{{{x}^{2}}}=0$
$\underset{x\to {{1}^{+}}}{\mathop{\lim }} c=c.$
Đáp án C.
