Có bao nhiêu số nguyên $x<25$ thỏa mãn $\left[\left(\log _3 3...

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\left[\left(\log _3 3 x\right)^2-4 \log _3 x\right]\left(4^x-18.2^x+32\right) \geq 0(1)
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+ĐK: $0<x<25 ; x \in Z$
$
\begin{aligned}
& (1) \Leftrightarrow\left[\left(\log _3 x\right)^2-2 \log _3 x+1\right]\left(4^x-18.2^x+32\right) \geq 0 \\
& \Leftrightarrow\left(\log _3 x-1\right)^2\left(4^x-18.2^x+32\right) \geq 0
\end{aligned}
$
$
\begin{aligned}
& +T H 1: \log _3 x-1=0 \Leftrightarrow x=3(t m) \\
& +T H 2: \log _3 x-1 \neq 0 \Leftrightarrow x \neq 3 \\
& (1) \Leftrightarrow 4^x-18.2^x+32 \geq 0 \\
& \Leftrightarrow\left[\begin{array} { l }
{ 2 ^ { x } \geq 2 ^ { 4 } } \\
{ 2 ^ { x } \leq 2 }
\end{array} \Leftrightarrow \left[\begin{array}{l}
x \geq 4 \\
x \leq 1
\end{array} \& 0<x<25 ; x \in Z \Rightarrow x \in\{1 ; 4 ; 5 ; \ldots ; 24\}\right.\right.
\end{aligned}
$