Trong không gian Oxyz, cho hai đường thẳng ${{d}_{1}}$ : $\left\{...

Đường thẳng \)">{{d}_{1}}M\left( 3;1;4 \right)\overrightarrow{{{u}_{1}}}=\left( 1;-2;0 \right){{d}_{2}}N\left( 2;4;1 \right)\overrightarrow{{{u}_{2}}}=\left( 1;0;-3 \right)\left\{ \begin{aligned}
& \left( P \right)//{{d}_{1}} \\
& \left( P \right)//{{d}_{2}} \\
\end{aligned} \right.\Rightarrow \left( P \right) \left[ \overrightarrow{{{u}_{1}}},\overrightarrow{{{u}_{2}}} \right]=\left( 6;3;2 \right)\left( R \right)A\left( 1;-2;1 \right)\Rightarrow \left( R \right)6\left( x-1 \right)+3\left( y+2 \right)+2\left( z-1 \right)=0\Rightarrow \left( R \right):6x+3y+2z-2=0M\left( 3;1;4 \right)N\left( 2;4;1 \right)\left( R \right)6x+3y+2z-2=0\Rightarrow \left( R \right):6x+3y+2z-2=0$ thỏa mãn.