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Câu hỏi: Tính tích phân $I=\int\limits_{0}^{1}{2020{{e}^{x}}dx}.$.
A. $I=2020e\left( e-1 \right).$
B. $I=2020e.$
C. $I=2020\left( e-1 \right).$
D. $I=2020\left( e-2 \right).$
A. $I=2020e\left( e-1 \right).$
B. $I=2020e.$
C. $I=2020\left( e-1 \right).$
D. $I=2020\left( e-2 \right).$
Ta có: $I=\int\limits_{0}^{1}{2020{{e}^{x}}dx}=2020{{e}^{x}}\left| \begin{aligned}
& ^{1} \\
& _{0} \\
\end{aligned} \right.=2020\left( e-1 \right)$.
& ^{1} \\
& _{0} \\
\end{aligned} \right.=2020\left( e-1 \right)$.
Đáp án C.