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Câu hỏi: Tìm số phức $z$ thỏa mãn $\left( 2-3i \right)z-\left( 9-2i \right)=\left( 1+i \right)z.$
A. $1+2i$.
B. $1-2i$.
C. $\dfrac{13}{5}+\dfrac{16}{5}i$.
D. $-1-2i$.
A. $1+2i$.
B. $1-2i$.
C. $\dfrac{13}{5}+\dfrac{16}{5}i$.
D. $-1-2i$.
$\left( 2-3i \right)z-\left( 9-2i \right)=\left( 1+i \right)z\Leftrightarrow \left[ \left( 2-3i \right)-\left( 1+i \right) \right]z=9-2i\Leftrightarrow z=\dfrac{9-2i}{1-4i}=1+2i.$
Đáp án A.