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Câu hỏi: Tìm nguyên hàm của hàm số $f(x)={{x}^{2}}-3x-\dfrac{1}{x}$
A. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}-\ln \left| x \right|+C$.
B. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}+\dfrac{1}{{{x}^{2}}}+C$.
C. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}-\ln x+C$.
D. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}+\ln \left| x \right|+C$.
A. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}-\ln \left| x \right|+C$.
B. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}+\dfrac{1}{{{x}^{2}}}+C$.
C. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}-\ln x+C$.
D. $\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}+\ln \left| x \right|+C$.
Ta có: $\int{{{x}^{2}}-3x-\dfrac{1}{x}dx=}\dfrac{{{x}^{3}}}{3}-3\dfrac{{{x}^{2}}}{2}-\ln \left| x \right|+C$
Đáp án A.