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Câu hỏi: Tìm nguyên hàm của hàm số $f\left( x \right)=4{{x}^{3}}+2x$.
A. $\int{f}(x)\text{d}x=12{{x}^{2}}+{{x}^{2}}+C$.
B. $\int{f}(x)\text{d}x=\dfrac{4}{3}{{x}^{4}}+{{x}^{2}}+C$.
C. $\int{f}(x)\text{d}x=12{{x}^{2}}+2+C$.
D. $\int{f}(x)\text{d}x={{x}^{4}}+{{x}^{2}}+C$.
A. $\int{f}(x)\text{d}x=12{{x}^{2}}+{{x}^{2}}+C$.
B. $\int{f}(x)\text{d}x=\dfrac{4}{3}{{x}^{4}}+{{x}^{2}}+C$.
C. $\int{f}(x)\text{d}x=12{{x}^{2}}+2+C$.
D. $\int{f}(x)\text{d}x={{x}^{4}}+{{x}^{2}}+C$.
Ta có $\int{f}(x)\text{d}x=\int{\left( 4{{x}^{3}}+2x \right)}\text{d}x={{x}^{4}}+{{x}^{2}}+C$.
Đáp án D.