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Câu hỏi: Tìm họ nguyên hàm của hàm số $f\left( x \right)={{x}^{2}}-3\sin x.$
A. $\int{f\left( x \right)dx=2x-3\cos x+C.}$
B. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}-3\cos x+C.}$
C. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}+3\cos x+C.}$
D. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}+\dfrac{1}{3}\cos x+C.}$
A. $\int{f\left( x \right)dx=2x-3\cos x+C.}$
B. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}-3\cos x+C.}$
C. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}+3\cos x+C.}$
D. $\int{f\left( x \right)dx=\dfrac{1}{3}{{x}^{3}}+\dfrac{1}{3}\cos x+C.}$
Ta có: $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}+3\cos x+C.$
Đáp án C.