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Câu hỏi: Tìm họ nguyên hàm của hàm số $f\left( x \right)={{e}^{2x+1}}$
A. $\int{f\left( x \right)\text{d}x}=2{{\text{e}}^{2x+1}}+C$.
B. $\int{f\left( x \right)\text{d}x}={{\text{e}}^{{{x}^{2}}+x}}+C$.
C. $\int{f\left( x \right)\text{d}x}=\dfrac{1}{2}{{\text{e}}^{2x+1}}+C$.
D. $\int{f\left( x \right)\text{d}x}={{\text{e}}^{2x+1}}+C$.
A. $\int{f\left( x \right)\text{d}x}=2{{\text{e}}^{2x+1}}+C$.
B. $\int{f\left( x \right)\text{d}x}={{\text{e}}^{{{x}^{2}}+x}}+C$.
C. $\int{f\left( x \right)\text{d}x}=\dfrac{1}{2}{{\text{e}}^{2x+1}}+C$.
D. $\int{f\left( x \right)\text{d}x}={{\text{e}}^{2x+1}}+C$.
Ta có $\int{f\left( x \right)\text{d}x}=\int{{{\text{e}}^{2x+1}}}\text{d}x=\dfrac{1}{2}{{\text{e}}^{2x+1}}+C$
Đáp án C.