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Câu hỏi: Tích phân $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}$ bằng
A. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. {{e}^{2x+1}} \right|_{0}^{\ln 3}$.
B. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{{{e}^{2x+1}}}{2x+1} \right|_{0}^{\ln 3}$.
C. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. {{e}^{2x}} \right|_{0}^{\ln 3}$.
D. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{1}{2}{{e}^{2x}} \right|_{0}^{\ln 3}$.
Ta có: $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{1}{2}{{e}^{2x}} \right|_{0}^{\ln 3}$.
A. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. {{e}^{2x+1}} \right|_{0}^{\ln 3}$.
B. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{{{e}^{2x+1}}}{2x+1} \right|_{0}^{\ln 3}$.
C. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. {{e}^{2x}} \right|_{0}^{\ln 3}$.
D. $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{1}{2}{{e}^{2x}} \right|_{0}^{\ln 3}$.
Ta có: $\int\limits_{0}^{\ln 3}{{{e}^{2x}}dx}=\left. \dfrac{1}{2}{{e}^{2x}} \right|_{0}^{\ln 3}$.
Đáp án D.