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Câu hỏi: Tích phân $\int\limits_{0}^{1}{{{\text{e}}^{3x}}\text{d}x}$ bằng
A. ${{\text{e}}^{3}}+\dfrac{1}{2}$.
B. $\text{e}-1$.
C. $\dfrac{{{\text{e}}^{3}}-\text{1}}{3}$.
D. ${{\text{e}}^{3}}-\text{1}$.
A. ${{\text{e}}^{3}}+\dfrac{1}{2}$.
B. $\text{e}-1$.
C. $\dfrac{{{\text{e}}^{3}}-\text{1}}{3}$.
D. ${{\text{e}}^{3}}-\text{1}$.
Ta có $\int\limits_{0}^{1}{{{\text{e}}^{3x}}\text{d}x}=\dfrac{1}{3}\int\limits_{0}^{1}{{{\text{e}}^{3x}}\text{d}\left( 3x \right)}=\left. \dfrac{1}{3}{{\text{e}}^{3x}} \right|_{0}^{1}=\dfrac{{{\text{e}}^{3}}-1}{3}$.Đáp án C.