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Câu hỏi: Tích phân $I=\int\limits_{0}^{2018}{{{2}^{x}}\text{d}x}$ bằng
A. ${{2}^{2018}}-1$.
B. $\dfrac{{{2}^{2018}}-1}{\ln 2}$.
C. $\dfrac{{{2}^{2018}}}{\ln 2}$.
D. ${{2}^{2018}}$.
A. ${{2}^{2018}}-1$.
B. $\dfrac{{{2}^{2018}}-1}{\ln 2}$.
C. $\dfrac{{{2}^{2018}}}{\ln 2}$.
D. ${{2}^{2018}}$.
$I=\int\limits_{0}^{2018}{{{2}^{x}}\text{d}x}=\left. \dfrac{{{2}^{x}}}{\ln 2} \right|_{0}^{2018}=\dfrac{{{2}^{2018}}-1}{\ln 2}$.
Đáp án D.