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Câu hỏi: Họ nguyên hàm của hàm số $f(x)=x-\sin 2x$ là
A. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}+\cos 2x+C$.
B. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}+\dfrac{1}{2}\cos 2x+C$.
C. $\int{f}(x)\text{d}x={{x}^{2}}+\dfrac{1}{2}\cos 2x+C$.
D. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}-\dfrac{1}{2}\cos 2x+C$.
A. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}+\cos 2x+C$.
B. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}+\dfrac{1}{2}\cos 2x+C$.
C. $\int{f}(x)\text{d}x={{x}^{2}}+\dfrac{1}{2}\cos 2x+C$.
D. $\int{f}(x)\text{d}x=\dfrac{{{x}^{2}}}{2}-\dfrac{1}{2}\cos 2x+C$.
Ta có : $\int{f}(x)\text{d}x=\int{\left( x-\sin 2x \right)}\text{d}x=\dfrac{{{x}^{2}}}{2}+\dfrac{1}{2}\cos 2x+C$.
Đáp án B.