Đốt cháy 14,56 gam bột Fe trong hỗn hợp khí gồm O2 và Cl2 (tỉ lệ...

$14,56\text{ Fe}:0,26\xrightarrow[C{{l}_{2}}:x]{{{O}_{2}}:x}m\text{ X}\xrightarrow{HCl}Y\left\{ \begin{aligned}
& F{{e}^{2+}}:y \\
& F{{e}^{3+}}:z \\
& C{{l}^{-}} \\
\end{aligned} \right.\xrightarrow{AgN{{O}_{3}}}109,8\left\{ \begin{aligned}
& AgCl \\
& Ag \\
\end{aligned} \right.$
${{n}_{HCl}}=2{{n}_{{{O}^{2-}}\left( X \right)}}=4{{n}_{{{O}_{2}}}}=4x\to {{n}_{AgCl}}={{n}_{C{{l}^{-}}}}=2x+4x=6x$
$F{{e}^{2+}}+A{{g}^{+}}\to F{{e}^{3+}}+Ag$
$\to {{n}_{Ag}}={{n}_{F{{e}^{2+}}}}=y$
$Y\left\{ \begin{aligned}
& F{{e}^{2+}}:y \\
& F{{e}^{3+}}:z \\
& C{{l}^{-}}:6x \\
\end{aligned} \right.\to \left\{ \begin{aligned}
& y+z=0,26 \\
& 2y+3z=6x\left( BTDT \right) \\
& 108y+143,5.6x=109,8 \\
\end{aligned} \right.\to \left\{ \begin{aligned}
& x=0,12 \\
& y=0,06 \\
& z=0,2 \\
\end{aligned} \right.$
$\to m={{m}_{Fe}}+{{m}_{{{O}_{2}}}}+{{m}_{C{{l}_{2}}}}=26,92$ (g).