Google
Câu hỏi: Cho $\int\limits_{0}^{1}{f\left( x \right)\text{d}x}=2018$ và $\int\limits_{0}^{1}{g\left( x \right)\text{d}x}=2019$, khi đó $\int\limits_{0}^{1}{\left( f\left( x \right)-3g\left( x \right) \right)\text{d}x}$ bằng
A. $-1$.
B. $-4037$.
C. $-4039$.
D. $-2019$.
A. $-1$.
B. $-4037$.
C. $-4039$.
D. $-2019$.
Ta có $\int\limits_{0}^{1}{\left( f\left( x \right)-3g\left( x \right) \right)\text{d}x}$ $=\int\limits_{0}^{1}{f\left( x \right)\text{d}x}-3\int\limits_{0}^{1}{g\left( x \right)\text{d}x}=-4039$.
Đáp án C.