Cho hàm số$$ $y=f\left( x \right)$ liên tục trên đoạn $\left[ -3;6...

Ta có hình vẽ sau Dựa vào hình vẽ ta có \)">F\left( 5 \right)-F\left( 4 \right)=\int\limits_{1}^{4}{f\left( x \right)dx}={{S}_{4}}=\dfrac{1.2}{2}=1\Rightarrow F\left( 5 \right)=7.F\left( 6 \right)-F\left( 5 \right)=\int\limits_{5}^{6}{f\left( x \right)dx}={{S}_{5}}=1.2=2\Rightarrow F\left( 6 \right)=9.F\left( 4 \right)-F\left( 3 \right)=\int\limits_{3}^{4}{f\left( x \right)dx}=-{{S}_{3}}=-\dfrac{1.2}{2}=-1\Rightarrow F\left( 3 \right)=7.F\left( 3 \right)-F\left( 1 \right)=\int\limits_{1}^{3}{f\left( x \right)dx}=-{{S}_{2}}=-\dfrac{2.2}{2}=-2\Rightarrow F\left( 1 \right)=9.F\left( 1 \right)-F\left( -3 \right)=\int\limits_{-3}^{1}{f\left( x \right)dx}={{S}_{1}}=\dfrac{4.4}{2}=8\Rightarrow F\left( -3 \right)=1.F\left( -3 \right)+2F\left( 1 \right)-F\left( 6 \right)=10.$