Google
Câu hỏi: Viết phương trình của phản ứng sau (nếu có):
a, Glucozơ tác dụng với nước brom
b,
Fructozơ $+{H_2}\buildrel {Ni,t^\circ } \over\longrightarrow $
c,
Fructozơ + $\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH$ $\buildrel {} \over\longrightarrow $
d,
Glucozơ + $\left[ {Ag{{\left({N{H_3}} \right)}_2}} \right]OH$ $\buildrel {} \over\longrightarrow $
a, Glucozơ tác dụng với nước brom
b,
Fructozơ $+{H_2}\buildrel {Ni,t^\circ } \over\longrightarrow $
c,
Fructozơ + $\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH$ $\buildrel {} \over\longrightarrow $
d,
Glucozơ + $\left[ {Ag{{\left({N{H_3}} \right)}_2}} \right]OH$ $\buildrel {} \over\longrightarrow $
a)
$C{H_2}OH{\left( {CHOH} \right)_4}CHO + B{r_2} + {H_2}O \Rightarrow C{H_2}OH{\left( {CHOH} \right)_4}COOH + 2HBr$
b,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_3} - C - C{H_2}OH + {H_2}\buildrel {Ni,t^\circ } \over\longrightarrow C{H_2}OH - {\left( {CHOH} \right)_4} - C{H_2}OH \cr & \;\left\| {} \right. \cr & \;O \cr} $
c,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_3} - C - C{H_2}OH \mathbin{\lower.3ex\hbox{$ \buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to. 5ex{\vss}}}} $}} C{H_2}OH - {\left( {CHOH} \right)_4} - CHO \cr & \;\;\;\;\;\;\;\left\| {} \right. \cr & \;\;\;\;\;\;O \cr} $
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_4} - CHO + 2\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH\buildrel {t^\circ } \over\longrightarrow C{H_2}OH{\left( {CHOH} \right)_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr & \cr} $
d,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_4} - CHO + 2\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH\buildrel {t^\circ } \over\longrightarrow C{H_2}OH{\left( {CHOH} \right)_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr & \cr} $
$C{H_2}OH{\left( {CHOH} \right)_4}CHO + B{r_2} + {H_2}O \Rightarrow C{H_2}OH{\left( {CHOH} \right)_4}COOH + 2HBr$
b,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_3} - C - C{H_2}OH + {H_2}\buildrel {Ni,t^\circ } \over\longrightarrow C{H_2}OH - {\left( {CHOH} \right)_4} - C{H_2}OH \cr & \;\left\| {} \right. \cr & \;O \cr} $
c,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_3} - C - C{H_2}OH \mathbin{\lower.3ex\hbox{$ \buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to. 5ex{\vss}}}} $}} C{H_2}OH - {\left( {CHOH} \right)_4} - CHO \cr & \;\;\;\;\;\;\;\left\| {} \right. \cr & \;\;\;\;\;\;O \cr} $
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_4} - CHO + 2\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH\buildrel {t^\circ } \over\longrightarrow C{H_2}OH{\left( {CHOH} \right)_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr & \cr} $
d,
$\eqalign{& C{H_2}OH - {\left( {CHOH} \right)_4} - CHO + 2\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]OH\buildrel {t^\circ } \over\longrightarrow C{H_2}OH{\left( {CHOH} \right)_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr & \cr} $