Câu hỏi: $\underset{x\to -\infty }{\mathop{\lim }} \dfrac{2{{\text{x}}^{2}}+4\text{x}-5}{-x+12}$ bằng A. $-\infty $ B. $-\dfrac{5}{12}$ C. $+\infty $ D. $-2$
Ta có $\underset{x\to -\infty }{\mathop{\lim }} \dfrac{2{{\text{x}}^{2}}+4\text{x}-5}{-x+12}=+\infty $