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Câu hỏi: Tính ${{\left( \sqrt[5]{8} \right)}^{{{\log }_{2}}243}}$
A. $27$.
B. $9$.
C. ${{3}^{\dfrac{29}{3}}}$.
D. $8$.
Ta có: ${{\left( \sqrt[5]{8} \right)}^{{{\log }_{2}}243}}={{8}^{\dfrac{1}{5}.{{\log }_{2}}{{3}^{5}}}}={{8}^{{{\log }_{2}}3}}={{\left( {{2}^{{{\log }_{2}}3}} \right)}^{3}}={{3}^{3}}=27$
A. $27$.
B. $9$.
C. ${{3}^{\dfrac{29}{3}}}$.
D. $8$.
Ta có: ${{\left( \sqrt[5]{8} \right)}^{{{\log }_{2}}243}}={{8}^{\dfrac{1}{5}.{{\log }_{2}}{{3}^{5}}}}={{8}^{{{\log }_{2}}3}}={{\left( {{2}^{{{\log }_{2}}3}} \right)}^{3}}={{3}^{3}}=27$
Đáp án A.