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Câu hỏi: Tìm nguyên hàm của hàm số $f\left( x \right)={{x}^{3}}-\dfrac{3}{{{x}^{2}}}$.
A. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}-\dfrac{3}{x}+C$.
B. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}+\dfrac{3}{x}+C$.
C. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}+\dfrac{1}{x}+C$.
D. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}-\dfrac{1}{x}+C$.
A. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}-\dfrac{3}{x}+C$.
B. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}+\dfrac{3}{x}+C$.
C. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}+\dfrac{1}{x}+C$.
D. $\int{f\left( x \right)\text{d}x=}\dfrac{{{x}^{4}}}{4}-\dfrac{1}{x}+C$.
Ta có: $\int{f\left( x \right)\text{d}x=}$ $\int{\left( {{x}^{3}}-\dfrac{3}{{{x}^{2}}} \right)\text{d}x=\int{{{x}^{3}}\text{d}x}}-\int{\dfrac{3}{{{x}^{2}}}\text{d}x}=$ $\dfrac{{{x}^{4}}}{4}+\dfrac{3}{x}+C$.
Đáp án B.