Google
Câu hỏi: Tìm nguyên hàm của hàm số $f\left( x \right)=\dfrac{2}{4x-3}$
A. $\int{\dfrac{2}{4x-3}\text{d}x}=\dfrac{1}{4}\ln \left| 4x-3 \right|+C$.
B. $\int{\dfrac{2}{4x-3}\text{d}x}=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C$.
C. $\int{\dfrac{2}{4x-3}\text{d}x}=2\ln \left| 4x-3 \right|+C$.
D. $\int{\dfrac{2}{4x-3}\text{d}x}=2\ln \left| 2x-\dfrac{3}{2} \right|+C$.
A. $\int{\dfrac{2}{4x-3}\text{d}x}=\dfrac{1}{4}\ln \left| 4x-3 \right|+C$.
B. $\int{\dfrac{2}{4x-3}\text{d}x}=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C$.
C. $\int{\dfrac{2}{4x-3}\text{d}x}=2\ln \left| 4x-3 \right|+C$.
D. $\int{\dfrac{2}{4x-3}\text{d}x}=2\ln \left| 2x-\dfrac{3}{2} \right|+C$.
Ta có: $\int{\dfrac{2}{4x-3}\text{d}x}=\int{\dfrac{1}{2x-\dfrac{3}{2}}\text{d}x}=\dfrac{1}{2}\int{\dfrac{\text{d}\left( 2x-\dfrac{3}{2} \right)}{2x-\dfrac{3}{2}}}=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C$.
Đáp án B.