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Câu hỏi: Tìm nguyên hàm của hàm số $f\left( x \right)=\dfrac{2}{4x-3}$
A. $\int{\dfrac{2dx}{4x-3}=2\ln \left( 2x-\dfrac{3}{2} \right)+C}$.
B. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C}$
C. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{2}\ln \left( 2x-\dfrac{3}{2} \right)+C}$.
D. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{4}\ln \left| 4x-3 \right|+C}$
A. $\int{\dfrac{2dx}{4x-3}=2\ln \left( 2x-\dfrac{3}{2} \right)+C}$.
B. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C}$
C. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{2}\ln \left( 2x-\dfrac{3}{2} \right)+C}$.
D. $\int{\dfrac{2dx}{4x-3}=\dfrac{1}{4}\ln \left| 4x-3 \right|+C}$
$\int{\dfrac{2}{4x-3}dx=\int{\dfrac{1}{2x-\dfrac{3}{2}}dx=\dfrac{1}{2}\ln \left| 2x-\dfrac{3}{2} \right|+C}}$.
Đáp án B.