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Câu hỏi: Tìm $\int{{{\sin }^{2}}2x\text{d}x}$
A. $\dfrac{\sin 4x}{8}+C$.
B. $\dfrac{x}{2}+\dfrac{\sin 4x}{8}+C$.
C. $-\dfrac{{{\cos }^{3}}3x}{3}+C$.
D. $\dfrac{x}{2}-\dfrac{\sin 4x}{8}+C$.
A. $\dfrac{\sin 4x}{8}+C$.
B. $\dfrac{x}{2}+\dfrac{\sin 4x}{8}+C$.
C. $-\dfrac{{{\cos }^{3}}3x}{3}+C$.
D. $\dfrac{x}{2}-\dfrac{\sin 4x}{8}+C$.
$\int{{{\sin }^{2}}2x\text{d}x}=\int{\left( \dfrac{1}{2}-\dfrac{1}{2}\cos 4x \right)}\text{d}x=\dfrac{x}{2}-\dfrac{\sin 4x}{8}+C$
Đáp án D.