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Câu hỏi: Tìm họ nguyên hàm của hàm số $f\left( x \right)={{x}^{2}}+\cos x+{{3}^{x}}$
A. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}-\sin x+\dfrac{{{3}^{x}}}{\ln 3}+C$
B. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}+\sin x+{{3}^{x}}\ln 3+C$
C. $\int{f\left( x \right)dx}=\dfrac{{{x}^{2}}}{3}-\sin x+{{3}^{x}}+C$
D. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}+\sin x+\dfrac{{{3}^{x}}}{\ln 3}+C$
A. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}-\sin x+\dfrac{{{3}^{x}}}{\ln 3}+C$
B. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}+\sin x+{{3}^{x}}\ln 3+C$
C. $\int{f\left( x \right)dx}=\dfrac{{{x}^{2}}}{3}-\sin x+{{3}^{x}}+C$
D. $\int{f\left( x \right)dx}=\dfrac{{{x}^{3}}}{3}+\sin x+\dfrac{{{3}^{x}}}{\ln 3}+C$
Ta có: $\int{f\left( x \right)dx}=\int{\left( {{x}^{2}}+\cos x+{{3}^{x}} \right)dx}=\dfrac{{{x}^{3}}}{3}+\sin x+\dfrac{{{3}^{x}}}{\ln 3}+C$
Đáp án D.