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Câu hỏi: Tìm họ nguyên hàm của hàm số $f\left( x \right)={{\text{e}}^{3x}}$.
A. $\int{f\left( x \right)\text{d}x=\dfrac{{{\text{e}}^{3x+1}}}{3x+1}}+C$.
B. $\int{f\left( x \right)\text{d}x=3{{\text{e}}^{3x}}}+C$.
C. $\int{f\left( x \right)\text{d}x={{\text{e}}^{3}}}+C$.
D. $\int{f\left( x \right)\text{d}x=\dfrac{{{\text{e}}^{3x}}}{3}}+C$.
A. $\int{f\left( x \right)\text{d}x=\dfrac{{{\text{e}}^{3x+1}}}{3x+1}}+C$.
B. $\int{f\left( x \right)\text{d}x=3{{\text{e}}^{3x}}}+C$.
C. $\int{f\left( x \right)\text{d}x={{\text{e}}^{3}}}+C$.
D. $\int{f\left( x \right)\text{d}x=\dfrac{{{\text{e}}^{3x}}}{3}}+C$.
Ta có: $\int{{{\text{e}}^{3x}}\text{d}x=\dfrac{{{\text{e}}^{3x}}}{3}}+C$.
Đáp án D.