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Câu hỏi: Tích phân $\int\limits_{1}^{2}{2{{x}^{4}}}\text{d}x$ bằng
A. $\dfrac{62}{5}$.
B. $\dfrac{5}{62}$.
C. $\dfrac{31}{5}$
D. $\dfrac{5}{31}$
A. $\dfrac{62}{5}$.
B. $\dfrac{5}{62}$.
C. $\dfrac{31}{5}$
D. $\dfrac{5}{31}$
Ta có: $\int\limits_{1}^{2}{2{{x}^{4}}}\text{d}x=2.\dfrac{{{x}^{5}}}{5}\left| \begin{matrix}
2 \\
1 \\
\end{matrix}=\dfrac{2}{5}.\left( {{2}^{5}}-{{1}^{5}} \right)=\dfrac{62}{5}. \right.$
2 \\
1 \\
\end{matrix}=\dfrac{2}{5}.\left( {{2}^{5}}-{{1}^{5}} \right)=\dfrac{62}{5}. \right.$
Đáp án A.