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Câu hỏi: Tích phân $\int\limits_{0}^{2}{{{e}^{2x+1}}dx}$ bằng
A. $\dfrac{{{e}^{5}}-e}{2}.$
B. $\dfrac{{{e}^{5}}+e}{2}.$
C. ${{e}^{5}}-e.$
D. ${{e}^{5}}+e.$
A. $\dfrac{{{e}^{5}}-e}{2}.$
B. $\dfrac{{{e}^{5}}+e}{2}.$
C. ${{e}^{5}}-e.$
D. ${{e}^{5}}+e.$
Ta có $\int\limits_{0}^{2}{{{e}^{2\text{x}+1}}d\text{x}}=\left. \dfrac{1}{2}{{e}^{2\text{x}+1}} \right|_{0}^{2}=\dfrac{{{e}^{5}}-e}{2}$.
Đáp án A.