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Câu hỏi: Tích phân $I=\int\limits_{0}^{\dfrac{\pi }{3}}{\sin xdx}$ bằng
A. $\dfrac{\sqrt{3}}{2}$
B. $-\dfrac{\sqrt{3}}{2}$
C. $\dfrac{1}{2}$
D. $-\dfrac{1}{2}$
A. $\dfrac{\sqrt{3}}{2}$
B. $-\dfrac{\sqrt{3}}{2}$
C. $\dfrac{1}{2}$
D. $-\dfrac{1}{2}$
Ta có $I=\int\limits_{0}^{\dfrac{\pi }{3}}{\sin xdx}=-\cos x\left| \begin{aligned}
& \dfrac{\pi }{3} \\
& 0 \\
\end{aligned} \right.=\dfrac{1}{2}.$
& \dfrac{\pi }{3} \\
& 0 \\
\end{aligned} \right.=\dfrac{1}{2}.$
Đáp án C.