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Câu hỏi: Rút gọn $P={{a}^{\sqrt{2}}}.{{\left( \dfrac{1}{a} \right)}^{\sqrt{2}-1}},a>0.$
A. ${{a}^{\sqrt{2}}}.$
B. $A.$
C. ${{a}^{2\sqrt{2}}}.$
D. ${{a}^{1-\sqrt{2}}}.$
A. ${{a}^{\sqrt{2}}}.$
B. $A.$
C. ${{a}^{2\sqrt{2}}}.$
D. ${{a}^{1-\sqrt{2}}}.$
$P={{a}^{\sqrt{2}}}.{{\left( \dfrac{1}{a} \right)}^{\sqrt{2}-1}}={{a}^{\sqrt{2}}}{{\left( {{a}^{-1}} \right)}^{\sqrt{2}-1}}={{a}^{\sqrt{2}}}{{a}^{1-\sqrt{2}}}=a$.
Đáp án B.