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Câu hỏi: Rút gọn biểu thức $P={{x}^{\dfrac{1}{2}}}.\sqrt[4]{x}$ với $x>0.$
A. $P={{x}^{\dfrac{3}{8}}}.$
B. $P={{x}^{\dfrac{1}{4}}}.$
C. $P={{x}^{\dfrac{3}{4}}}.$
D. $P={{x}^{\dfrac{1}{8}}}.$
A. $P={{x}^{\dfrac{3}{8}}}.$
B. $P={{x}^{\dfrac{1}{4}}}.$
C. $P={{x}^{\dfrac{3}{4}}}.$
D. $P={{x}^{\dfrac{1}{8}}}.$
Ta có: $P={{x}^{\dfrac{1}{2}}}.{{x}^{\dfrac{1}{4}}}={{x}^{\dfrac{1}{2}+\dfrac{1}{4}}}={{x}^{\dfrac{3}{4}}}$.
Đáp án C.