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Câu hỏi: Phương trình mặt cầu có tâm $I\left( -1;2;-3 \right)$, bán kính $R=2\sqrt{2}$ là:
A. ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-3 \right)}^{2}}=8$.
B. ${{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+3 \right)}^{2}}=2\sqrt{2}$.
C. ${{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+3 \right)}^{2}}=8$.
D. ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-3 \right)}^{2}}=2\sqrt{2}$.
A. ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-3 \right)}^{2}}=8$.
B. ${{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+3 \right)}^{2}}=2\sqrt{2}$.
C. ${{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+3 \right)}^{2}}=8$.
D. ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-3 \right)}^{2}}=2\sqrt{2}$.
Mặt cầu tâm $I\left( -1;2;-3 \right)$, bán kính $R=2\sqrt{2}$ có phương trình: ${{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+3 \right)}^{2}}=8$.
Đáp án C.