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Câu hỏi: Nguyên hàm $F\left( x \right)$ của hàm số $f\left( x \right)={{x}^{3}}-x+1$
A. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+x$.
B. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+x+C$.
C. $F\left( x \right)=3{{x}^{2}}-1$.
D. $F\left( x \right)={{x}^{4}}-{{x}^{2}}+1+C$.
A. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+x$.
B. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+x+C$.
C. $F\left( x \right)=3{{x}^{2}}-1$.
D. $F\left( x \right)={{x}^{4}}-{{x}^{2}}+1+C$.
Ta có: $F\left( x \right)$ = $\int{f\left( x \right)}dx=\int{\left( {{x}^{3}}-x+1 \right)}dx$ = $\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+x+C$.
Đáp án B.