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Câu hỏi: Nguyên hàm của hàm số $f(x)=\sqrt{3x+2}$ là
A. $\dfrac{2}{3}\left( 3x+2 \right)\sqrt{3x+2}+C.$
B. $\dfrac{1}{3}\left( 3x+2 \right)\sqrt{3x+2}+C.$
C. $\dfrac{2}{9}\left( 3x+2 \right)\sqrt{3x+2}+C.$
D. $\dfrac{3}{2}\dfrac{1}{\sqrt{3x+2}}+C.$
A. $\dfrac{2}{3}\left( 3x+2 \right)\sqrt{3x+2}+C.$
B. $\dfrac{1}{3}\left( 3x+2 \right)\sqrt{3x+2}+C.$
C. $\dfrac{2}{9}\left( 3x+2 \right)\sqrt{3x+2}+C.$
D. $\dfrac{3}{2}\dfrac{1}{\sqrt{3x+2}}+C.$
$\int{\sqrt{3x+2}dx}=\int{{{\left( 3x+2 \right)}^{\dfrac{1}{2}}}dx=\dfrac{2}{3}.\dfrac{1}{3}{{\left( 3x+2 \right)}^{\dfrac{3}{2}}}+C}$.
Đáp án C.