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Câu hỏi: Nguyên hàm của hàm số $f\left( x \right)={{x}^{3}}+3\text{x}+2$ là hàm số nào trong hàm số sau
A. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}+\dfrac{3{{\text{x}}^{2}}}{2}+2\text{x}+C\cdot $
B. $F\left( x \right)={{x}^{4}}+3{{\text{x}}^{2}}+2\text{x}+C\cdot $
C. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}+\dfrac{{{\text{x}}^{2}}}{2}+2\text{x}+C\cdot $
D. $F\left( x \right)=3{{\text{x}}^{2}}+3+C\cdot $
A. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}+\dfrac{3{{\text{x}}^{2}}}{2}+2\text{x}+C\cdot $
B. $F\left( x \right)={{x}^{4}}+3{{\text{x}}^{2}}+2\text{x}+C\cdot $
C. $F\left( x \right)=\dfrac{{{x}^{4}}}{4}+\dfrac{{{\text{x}}^{2}}}{2}+2\text{x}+C\cdot $
D. $F\left( x \right)=3{{\text{x}}^{2}}+3+C\cdot $
Vì ${{\left[ F\left( x \right) \right]}^{\prime }}={{\left( \dfrac{{{x}^{4}}}{4}+\dfrac{3{{\text{x}}^{2}}}{2}+2\text{x}+C \right)}^{\prime }}={{x}^{3}}+3\text{x}+2=f\left( x \right)$.
Đáp án A.