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Câu hỏi: Nếu $\int\limits_{-1}^{1}{f}(x)\text{d}x=5$ thì $\int\limits_{-1}^{1}{(f}(x)+3{{x}^{2}}\text{-2x+1)d}x$ bằng
A. 9.
B. 10.
C. 13
D. 12.
A. 9.
B. 10.
C. 13
D. 12.
$\begin{aligned}
& \int\limits_{-1}^{1}{(f}(x)+3{{x}^{2}}\text{-2x+1)d}x=\int\limits_{-1}^{1}{f}(x)\text{d}x+\int\limits_{-1}^{1}{(3}{{x}^{2}}\text{-2x+1)d}x \\
& =5+({{x}^{3}}-{{x}^{2}}+x)|_{-1}^{1}=5+4=9 \\
\end{aligned}$
& \int\limits_{-1}^{1}{(f}(x)+3{{x}^{2}}\text{-2x+1)d}x=\int\limits_{-1}^{1}{f}(x)\text{d}x+\int\limits_{-1}^{1}{(3}{{x}^{2}}\text{-2x+1)d}x \\
& =5+({{x}^{3}}-{{x}^{2}}+x)|_{-1}^{1}=5+4=9 \\
\end{aligned}$
Đáp án A.