Google
Câu hỏi: Nếu ${\int\limits_{0}^{1}{f\left( x \right)}\text{d}x=-2}$ và ${\int\limits_{0}^{1}{g\left( x \right)}\text{d}x=1}$ thì ${\int\limits_{0}^{1}{\left[ 2022f\left( x \right)+2023g\left( x \right) \right]}\text{d}x}$ bằng
A. $-2021$.
B. $-2023$.
C. $-2022$.
D. $4045$.
A. $-2021$.
B. $-2023$.
C. $-2022$.
D. $4045$.
Ta có $\int\limits_{0}^{1}{\left[ 2022f\left( x \right)+2023g\left( x \right) \right]}\text{d}x=2022\int\limits_{0}^{1}{f\left( x \right)}\text{d}x+2023\int\limits_{0}^{1}{g\left( x \right)}\text{d}x=-2021$.
Đáp án A.