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Câu hỏi: Khối cầu $\left( S \right)$ có diện tích mặt cầu bằng $16\pi $ (đvdt). Tính thể tích khối cầu.
A. $\dfrac{32\pi }{9}\left( vdt \right)$.
B. $\dfrac{32\pi }{3}\left( vdt \right)$.
C. $\dfrac{32\pi \sqrt{3}}{9}\left( vdt \right)$.
D. $\dfrac{32\pi \sqrt{3}}{3}\left( vdt \right)$.
A. $\dfrac{32\pi }{9}\left( vdt \right)$.
B. $\dfrac{32\pi }{3}\left( vdt \right)$.
C. $\dfrac{32\pi \sqrt{3}}{9}\left( vdt \right)$.
D. $\dfrac{32\pi \sqrt{3}}{3}\left( vdt \right)$.
$S=4\pi {{R}^{2}}=16\pi \Rightarrow {{R}^{2}}=\dfrac{16\pi }{4\pi }=4\Rightarrow R=2$.
$V=\dfrac{4}{3}\pi {{R}^{3}}=\dfrac{4}{3}\pi {{.2}^{3}}=\dfrac{32\pi }{3}\left( vdt \right)$.
$V=\dfrac{4}{3}\pi {{R}^{3}}=\dfrac{4}{3}\pi {{.2}^{3}}=\dfrac{32\pi }{3}\left( vdt \right)$.
Đáp án B.
