$\int_2^5(3 x-4)^4 \mathrm{~d} x$ bằng

Ta có: $\int(a x+b)^n \mathrm{~d} x=\dfrac{1}{a} \cdot \dfrac{(a x+b)^{n+1}}{n+1}+C$.
Suy ra: $\int_2^5(3 x-4)^4 \mathrm{~d} x=\left.\dfrac{1}{3} \cdot \dfrac{(3 x-4)^5}{5}\right|_2 ^5=\dfrac{1}{3} \cdot \dfrac{(3.5-4)^5}{5}-\dfrac{1}{3} \cdot \dfrac{(3.2-4)^5}{5}=\dfrac{53673}{5}$.