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Câu hỏi: Họ nguyên hàm $\int{\dfrac{1}{{{x}^{2}}-x}}dx$ là
A. $-\ln \left| x\left( x-1 \right) \right|+C$.
B. $\ln \left| \dfrac{x}{x-1} \right|+C$.
C. $\ln \left| \dfrac{x-1}{x} \right|+C$.
D. $\ln \left| x\left( x-1 \right) \right|+C$.
A. $-\ln \left| x\left( x-1 \right) \right|+C$.
B. $\ln \left| \dfrac{x}{x-1} \right|+C$.
C. $\ln \left| \dfrac{x-1}{x} \right|+C$.
D. $\ln \left| x\left( x-1 \right) \right|+C$.
Ta có $\int{\dfrac{1}{{{x}^{2}}-x}}dx=\int{\dfrac{dx}{x(x-1)}}=\int{\left( \dfrac{1}{x-1}-\dfrac{1}{x} \right)dx=\ln \left| \dfrac{x-1}{x} \right|}+C$.
Đáp án C.