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Câu hỏi: Họ nguyên hàm của hàm số $f\left( x \right)={{e}^{x}}+1$ là
[/LIST]A. $F\left( x \right)={{e}^{x}}-x+C$.
[/LIST]B. $F\left( x \right)=\dfrac{1}{x+1}{{e}^{x+1}}+x+C$.
[/LIST]C. $F\left( x \right)={{e}^{x}}+x+C$.
[/LIST]D. $F\left( x \right)=x{{e}^{x-1}}+x+C$.
[/LIST]A. $F\left( x \right)={{e}^{x}}-x+C$.
[/LIST]B. $F\left( x \right)=\dfrac{1}{x+1}{{e}^{x+1}}+x+C$.
[/LIST]C. $F\left( x \right)={{e}^{x}}+x+C$.
[/LIST]D. $F\left( x \right)=x{{e}^{x-1}}+x+C$.
[/LIST]
Ta có: $F\left( x \right)=\int{\left( {{e}^{x}}+1 \right)\text{d}x}={{e}^{x}}+x+C$.
Ta có: $F\left( x \right)=\int{\left( {{e}^{x}}+1 \right)\text{d}x}={{e}^{x}}+x+C$.
Đáp án C.