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Câu hỏi: Hàm số $f\left( x \right)={{2}^{{{x}^{2}}+3x+1}}$ có đạo hàm là
A. ${f}'\left( x \right)={{2}^{{{x}^{2}}+3x+1}}\left( 2x+3 \right)$
B. ${f}'\left( x \right)=\dfrac{2x+3}{{{2}^{{{x}^{2}}+3x+1}}.\ln 2}$
C. ${f}'\left( x \right)={{2}^{{{x}^{2}}+3x+1}}\left( 2x+3 \right)\ln 2$
D. ${f}'\left( x \right)=\dfrac{2x+3}{{{2}^{{{x}^{2}}+3x+1}}}$
A. ${f}'\left( x \right)={{2}^{{{x}^{2}}+3x+1}}\left( 2x+3 \right)$
B. ${f}'\left( x \right)=\dfrac{2x+3}{{{2}^{{{x}^{2}}+3x+1}}.\ln 2}$
C. ${f}'\left( x \right)={{2}^{{{x}^{2}}+3x+1}}\left( 2x+3 \right)\ln 2$
D. ${f}'\left( x \right)=\dfrac{2x+3}{{{2}^{{{x}^{2}}+3x+1}}}$
${f}'\left( x \right)={{2}^{{{x}^{2}}+3x+1}}\left( {{x}^{2}}+3x+1 \right)'\ln 2={{2}^{{{x}^{2}}+3x+1}}\left( 2x+3 \right)\ln 2$
Đáp án C.