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Câu hỏi: Đốt cháy hoàn toàn
A. 7,612 gam.
B. 7,512 gam.
C. 7,412 gam.
D. 7,312 gsm.
A. 7,612 gam.
B. 7,512 gam.
C. 7,412 gam.
D. 7,312 gsm.
$\begin{aligned}
& \xrightarrow{BT.O}6{{n}_{X}}+2{{n}_{{{O}_{2}}}}=2{{n}_{C{{O}_{2}}}}+{{n}_{{{H}_{2}}O}}\to {{n}_{X}}=\dfrac{1,14.2+1,06-2.1,61}{6}=0,02\ mol \
& \xrightarrow{BTKL}{{m}_{X}}={{m}_{C{{O}_{2}}}}+{{m}_{{{H}_{2}}O}}-{{m}_{{{O}_{2}}}}=17,72\ gam \
\end{aligned}$
& \xrightarrow{BT.O}6{{n}_{X}}+2{{n}_{{{O}_{2}}}}=2{{n}_{C{{O}_{2}}}}+{{n}_{{{H}_{2}}O}}\to {{n}_{X}}=\dfrac{1,14.2+1,06-2.1,61}{6}=0,02\ mol \
& \xrightarrow{BTKL}{{m}_{X}}={{m}_{C{{O}_{2}}}}+{{m}_{{{H}_{2}}O}}-{{m}_{{{O}_{2}}}}=17,72\ gam \
\end{aligned}$
Đáp án D.