Điện phân nóng chảy Al2O3 với anot than chì (hiệu suất điện phân...

$A{{l}_{2}}{{O}_{3}}\xrightarrow{C,t{}^\circ }\left\{ \begin{aligned}
& Al: \\
& 67,2{{\text{m}}^{3}}\left\{ \begin{aligned}
& C{{O}_{2}} \\
& CO \\
& {{O}_{2}} \\
\end{aligned} \right.\overline{M}=32 \\
\end{aligned} \right.$
${{n}_{C{{O}_{2}}}}={{n}_{CaC{{\text{O}}_{3}}}}=0,02\text{ mol}\to {{\text{n}}_{C{{O}_{2}}\left( 67,2{{\text{m}}^{3}}\text{ X} \right)}}=\dfrac{0,02.67,2.1000}{2,24}=600$
$3000\text{ mol X}\left\{ \begin{aligned}
& C{{O}_{2}}:600 \\
& CO:a \\
& {{O}_{2}}:b \\
\end{aligned} \right.$
$\to \left\{ \begin{aligned}
& a+b+600=3000 \\
& 28\text{a}+32b+44.600=32.3000\left( {{m}_{X}} \right) \\
\end{aligned} \right.\to \left\{ \begin{aligned}
& a=1800 \\
& b=600 \\
\end{aligned} \right.$
BT O: $3{{n}_{A{{l}_{2}}{{O}_{3}}}}={{n}_{O\left( X \right)}}=2{{n}_{C{{O}_{2}}}}+{{n}_{CO}}+2{{n}_{{{O}_{2}}}}=4200$
$\to {{n}_{A{{l}_{2}}{{O}_{3}}}}=1400\to {{n}_{Al}}=2{{n}_{A{{l}_{2}}{{O}_{3}}}}=2800$
$\to {{m}_{Al}}=75600=75,6$ kg