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Câu hỏi: Đạo hàm của hàm số $y=(2 x-1)^{\dfrac{1}{3}}$ là
A. $y^{\prime}=\dfrac{1}{3}(2 x-1)^{-\dfrac{2}{3}}$
B. $y^{\prime}=(2 x-1)^{\dfrac{1}{3}} \cdot \ln |2 x-1|$.
C. $y^{\prime}=\dfrac{2}{3}(2 x-1)^{\dfrac{4}{3}}$.
D. $y^{\prime}=\dfrac{2}{3}(2 x-1)^{-\dfrac{2}{3}}$.
A. $y^{\prime}=\dfrac{1}{3}(2 x-1)^{-\dfrac{2}{3}}$
B. $y^{\prime}=(2 x-1)^{\dfrac{1}{3}} \cdot \ln |2 x-1|$.
C. $y^{\prime}=\dfrac{2}{3}(2 x-1)^{\dfrac{4}{3}}$.
D. $y^{\prime}=\dfrac{2}{3}(2 x-1)^{-\dfrac{2}{3}}$.
Ta có: $y^{\prime}=\dfrac{1}{3}(2 x-1)^{-\dfrac{2}{3}} \cdot(2 x-1)^{\prime}=\dfrac{2}{3}(2 x-1)^{-\dfrac{2}{3}}$.
Đáp án D.