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Câu hỏi: Đạo hàm của hàm số $f\left( x \right)={{6}^{1-3x}}$ là:
A. ${f}'\left( x \right)=-{{3.6}^{1-3x}}.\ln 6$.
B. ${f}'\left( x \right)=-{{6}^{1-3x}}.\ln 6$.
C. ${f}'\left( x \right)=-x{{.6}^{1-3x}}.\ln 6$.
D. ${f}'\left( x \right)=\left( 1-3x \right){{.6}^{-3x}}$.
A. ${f}'\left( x \right)=-{{3.6}^{1-3x}}.\ln 6$.
B. ${f}'\left( x \right)=-{{6}^{1-3x}}.\ln 6$.
C. ${f}'\left( x \right)=-x{{.6}^{1-3x}}.\ln 6$.
D. ${f}'\left( x \right)=\left( 1-3x \right){{.6}^{-3x}}$.
$f\left( x \right)={{6}^{1-3x}}\Rightarrow {f}'\left( x \right)={{\left( 1-3x \right)}^{\prime }}{{.6}^{1-3x}}.\ln 6=-{{3.6}^{1-3x}}.\ln 6$.
Đáp án A.