T

Cho sơ đồ chuyển hóa sau: $Cr\xrightarrow[{}]{+HCl\left( l...

Câu hỏi: Cho sơ đồ chuyển hóa sau:
$Cr\xrightarrow[{}]{+HCl\left( l \right)}\left( X \right)\xrightarrow[{}]{+C{{l}_{2}},t{}^\circ }\left( M \right)\xrightarrow[{}]{+B{{r}_{2}}+KOH}\left( Z \right)\xrightarrow[{}]{+{{H}_{2}}S{{O}_{4}}\left( l \right)}\left( T \right)\xrightarrow[{}]{FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}\left( Y \right)$
T và Y lần lượt là?
A. ${{K}_{2}}Cr{{O}_{4}}$ và $C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$.
B. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $CrC{{l}_{3}}$.
C. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $CrS{{O}_{4}}$.
D. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$.
$Cr\xrightarrow[{}]{+HCl\left( l \right)}CrC{{l}_{2}}\xrightarrow[{}]{+C{{l}_{2}}}CrC{{l}_{3}}\xrightarrow[{}]{+B{{r}_{2}}+KOH}{{K}_{2}}Cr{{O}_{4}}$
$\xrightarrow[{}]{{{H}_{2}}S{{O}_{4}}\text{ loa }\!\!\tilde{\mathrm{o}}\!\!\text{ ng}}{{K}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow[{}]{FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$
Có các phương trình:
1) $Cr+2HC{{l}_{\left( l \right)}}\xrightarrow[{}]{{}}CrC{{l}_{2}}\left( X \right)+{{H}_{2}}$
2) $2CrC{{l}_{2}}+C{{l}_{2}}\xrightarrow[{}]{t{}^\circ }2CrC{{l}_{3}}\left( Y \right)$
3) $2CrC{{l}_{3}}+3B{{r}_{2}}+16KOH\xrightarrow[{}]{{}}2{{K}_{2}}Cr{{O}_{4}}\left( Z \right)+6KBr+6KCl+8{{H}_{2}}O$
4) $2{{K}_{2}}Cr{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}{{K}_{2}}C{{r}_{2}}{{O}_{7}}\left( T \right)+{{K}_{2}}S{{O}_{4}}+{{H}_{2}}O$
5) $6FeS{{O}_{4}}+{{K}_{2}}C{{r}_{2}}{{O}_{7}}+7{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}3F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\left( M \right)+{{K}_{2}}S{{O}_{4}}+7{{H}_{2}}O$
Đáp án D.
 

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