Cho phương trình $2{{\log }_{3}}\left( {{x}^{3}}+1 \right)={{\log...

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$\Leftrightarrow \left| 2x-1 \right|={{x}^{2}}-x+1\Leftrightarrow \left[ \begin{aligned}
& 2x-1={{x}^{2}}-x+1 \\
& 2x-1=-\left( {{x}^{2}}-x+1 \right) \\
\end{aligned} \right.$$\Leftrightarrow \left[ \begin{aligned}
& {{x}^{2}}-3x+2=0 \\
& {{x}^{2}}+x=0 \\
\end{aligned} \right.\Leftrightarrow \left[ \begin{aligned}
& x=1 \\
& x=2 \\
& x=0 \\
& x=-1 \\
\end{aligned} \right.0, 1, 2.3$.