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Câu hỏi: Cho $\int\limits_{0}^{2}{f\left( x \right)\text{d}x=5}$. Tính tích phân $I=\int\limits_{0}^{2}{\left[ {{x}^{2}}+2f\left( x \right) \right]\text{d}x}$.
A. 18.
B. $\dfrac{38}{3}$.
C. $\dfrac{23}{3}$.
D. $\dfrac{46}{3}$.
A. 18.
B. $\dfrac{38}{3}$.
C. $\dfrac{23}{3}$.
D. $\dfrac{46}{3}$.
Ta có: $I=\int\limits_{0}^{2}{\left[ {{x}^{2}}+2f\left( x \right) \right]\text{d}x}=$ $\int\limits_{0}^{2}{{{x}^{2}}\text{d}x+2\int\limits_{0}^{2}{f\left( x \right)\text{d}x}}=\dfrac{8}{3}+2.5=\dfrac{38}{3}$.
Đáp án B.