Cho hỗn hợp X gồm amino axit Y...

$X\left\{ \begin{aligned}
& \overbrace{{{H}_{2}}N{{C}_{x}}{{H}_{y}}COOH}^{(Y)}:a mol \\
& {{\left( {{H}_{2}}N \right)}_{2}}{{C}_{5}}{{H}_{9}}COOH:0,01 mol \\
\end{aligned} \right.\xrightarrow{+HCl:0,05 mol}Z\xrightarrow{+\left\{ \begin{smallmatrix}
NaOH:0,02 mol \\
KOH:0,06 mol
\end{smallmatrix} \right.}\underbrace{mu\grave{e}i}_{8,345 gam}$
$\to 8,345 gam\left\{ \begin{aligned}
& N{{a}^{+}}:0,02 mol \\
& {{K}^{+}}:0,06 mol \\
& C{{l}^{-}}:0,05mol \\
& {{\left( {{H}_{2}}N \right)}_{2}}{{C}_{5}}{{H}_{9}}CO{{O}^{-}}:0,01 mol \\
& {{H}_{2}}N{{C}_{x}}{{H}_{y}}CO{{O}^{-}}:a mol \\
\end{aligned} \right.$
$\left\{ \begin{aligned}
& \xrightarrow{BTDT}0,02.1+0,06.1=0,05.1+0,01.1+a \\
& \xrightarrow{BTKL}{{m}_{mu\grave{e}i}}=23.0,02+0,06.39+0,05.35,5+0,01.145+(12x+y+60).a=8,345 \\
\end{aligned} \right.$
$\Rightarrow \left\{ \begin{aligned}
& a=0,02 (mol) \\
& 12x+y=56 \\
\end{aligned} \right.$
$\to x=4 v\mu y=8 $ thỏa mãn.
Y có CTCT: ${{H}_{2}}N-{{C}_{4}}{{H}_{8}}-COOH$ với ${{M}_{Y}}=117.$
$\to $ Chọn đáp án D.