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Câu hỏi: Cho hàm số $f\left( x \right)$ liên tục trên $\left[ 0;10 \right]$ thỏa mãn $\int\limits_{0}^{10}{f\left( x \right)\text{d}x=7} $, $\int\limits_{2}^{6}{f\left( x \right)\text{d}x=3}$. Giá trị $P=\int\limits_{0}^{2}{f\left( x \right)\text{d}x}+\int\limits_{6}^{10}{f\left( x \right)\text{d}x}$ là
A. $10.$
B. $-4.$
C. $4.$
D. $7.$
Ta có $7=\int\limits_{0}^{10}{f\left( x \right)\text{d}x}$ $=\int\limits_{0}^{2}{f\left( x \right)\text{d}x}+\int\limits_{2}^{6}{f\left( x \right)\text{d}x+\int\limits_{6}^{10}{f\left( x \right)\text{d}x} }$ nên $P=7-\int\limits_{2}^{6}{f\left( x \right)\text{d}x=}$ $7-3=4$.$$
A. $10.$
B. $-4.$
C. $4.$
D. $7.$
Ta có $7=\int\limits_{0}^{10}{f\left( x \right)\text{d}x}$ $=\int\limits_{0}^{2}{f\left( x \right)\text{d}x}+\int\limits_{2}^{6}{f\left( x \right)\text{d}x+\int\limits_{6}^{10}{f\left( x \right)\text{d}x} }$ nên $P=7-\int\limits_{2}^{6}{f\left( x \right)\text{d}x=}$ $7-3=4$.$$
Đáp án C.